hey just wondering where I went wrong(adsbygoogle = window.adsbygoogle || []).push({});

Iridium Crystallizes in a face centred cubic unit call that has an edge length of 3.833A

The atom in the cantre of the face is in contact with the corner atoms

calculate the atomic radii of the irridium atom

I did this

using pythag, (3.833^2)+(3.833^2)=c^2

b^2= 29.384

b=5.42

Then I divided it by 2 as it was the radius and got 2.710

But I am assuming that this is wrong due to the qu asking for the atomic radii. So I divide it by 192.272 and I still get the wrong answer.

The answer is meant to be 1.355Angstrom

So if anyone could tell me where I went wrong I would be much appreciative

Thanks

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# Homework Help: Atomic radii for irridium

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