- #1

- 128

- 2

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- #1

- 128

- 2

- #2

- 139

- 0

spin up-spin up

spin down-spin down

spin up-spin down

These configurations are different in energy.

- #3

- 128

- 2

- #4

- 980

- 2

So the answer to your question is that different alignments of spin and angular momentum give different energies.

If you want, I can work through some examples of calculating the allowed states, their term symbols and their relative energies (qualitatively).

- #5

- 128

- 2

But, what I am basically trying to do is to calculate the energy of excited states of some atoms without the effect of spin-orbit. Now, let's say I have an atom with the configuration [tex][Ar]3d^2[/tex] so that the two outermost electrons are d electrons and the only shell which is not full is this d shell. If the two electrons are assumed to be spin-up electrons, I get two different terms, a 3F term and a 3P term. Now, there's some energy difference between these two terms right? I just don't understand why, because the electron configuration is given and I assumed that the electrons are both spin-up electrons. So how can these two terms differ in energy? Maybe I've misunderstood something.

- #6

- 980

- 2

- #7

- 2

- 0

L = l1+ l2, l1+ l2 -1, l1+ l2 -2,… |l1- l2|.

- #8

- 2

- 0

[tex]L = l_1+ l_2, l_1+ l_2 -1, l_1+ l_2 -2,… |l_1- l_2|. [/tex]

Share:

- Replies
- 1

- Views
- 432

- Replies
- 3

- Views
- 452

- Replies
- 5

- Views
- 384

- Replies
- 4

- Views
- 582

- Replies
- 3

- Views
- 705

- Replies
- 4

- Views
- 508

- Replies
- 8

- Views
- 608

- Replies
- 11

- Views
- 586

- Replies
- 7

- Views
- 631

- Replies
- 1

- Views
- 372