1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Attenuation length

  1. Oct 15, 2007 #1
    1. The problem statement, all variables and given/known data

    Show that the attenuation length, [tex]\Lambda[/tex], is just equal to the average distance a photon travels before being scattered or absorbed.

    2. Relevant equations

    my book gives:

    number of photons absorbed = [tex]\sigma\rho I(x) dx[/tex]

    number of photons present after a thickness x = [tex]I(x)=I(0)e^{-\sigma \rho x}[/tex]

    attenuation length = [tex]\Lambda = \frac{1}{\sigma\rho}[/tex]

    3. The attempt at a solution

    i'm really not sure where to go here... some idea on how to get started would be very much appreciated... thanks
     
    Last edited: Oct 15, 2007
  2. jcsd
  3. Oct 15, 2007 #2
    ok, nevermind, I think I got it...

    [tex]x_{avg}=\int^{\infty}_{0}x \sigma \rho e^{\sigma \rho} dx [/tex]

    (i think)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Attenuation length
  1. Sound attenuation (Replies: 1)

Loading...