(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Consider the Atwood's machine of Lecture 8. We wish to use this machine to measure our local acceleration of gravity with an accuracy of 5% [i.e. (Delta g)/g = 0.05]. To begin, suppose we let the mass m_1 fall through a distance L.

3.1 Find an expression for the acceleration of gravity, g, in terms of m_1, m_2, L and t.

3.2 Now suppose we are able to measure time with an accuracy of (Delta t) = 0.1 s. Assuming that, for example, (Delta t)/t can be approximated by the differential dt/t, write the relationship between (Delta g)/g and (Delta t)/t. You can do this by starting with the derivative dg/dt determined from the equation in the previous part.

3.3 If L = 3 m and m_1 = 1 kg, determine the value of m_2 required to determine g to 5%. If we want to measure g to 1% would the mass m_2 increase or decrease - why? (On your own, you might want to consider the effect of the uncertainty in the masses of m_1 and m_2 on the determination of g.)

2. Relevant equations

F=ma

x-x_0=v_o*t+.5*a*t^2

3. The attempt at a solution

3.1

First I summed up the forces on the two masses and solved for the acceleration of the blocks.

I ended up with...

a=g(m1-m2)/(m1+m2)

Then I used x-x_0=v_o*t+.5*a*t^2 and solved for the acceleration.

a=2L/t^2

Combing the two equations and solving for gravity I got...

g=(2L(m1+m2))/((m1-m2)t^2)

3.2

I took the derivative of both sides of the equation with respect to t and got...

dg/dt=(-4L(m1+m2))/((m1-m2)t^3)

My attempt to relate dg/g to dt/t

dg/g=(-4L(m1+m2))dt / ((m1-m2)gt^3)

And that's where I'm stuck. I'm not sure if I did everything right and I can't figure out what I have to plug in to do part 3.3

Any help is appreciated. Thank you!!!

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# Homework Help: Atwood Machine and gravity

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