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Homework Help: Atwood Machine simulation problem

  1. Jan 23, 2005 #1
    Need a check on this one please. In an Atwood Machine simulation, m1 is 1.0kg and m2 is 1.1kg. m2 rests on the floor that exerts a normal force, Fn, on m2. when the system is in equalibrium, the tension, T, in the rope at 2.54s is 9.789. If Fn +T- m2*g = 0 then Fn = .991. Is this correct?
     
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  3. Jan 24, 2005 #2

    Doc Al

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    Staff: Mentor

    equilibrium

    If the question is "What normal force does the floor exert on m2 when m2 rests on the floor?" then you're probably OK. (Although I have no idea what 2.54s has to do with anything.)

    The forces on m2 are: [itex]F_n + T - m_2 g = 0[/itex]; similarly, the forces on m1 are: [itex]T - m_1 g = 0[/itex]. So [itex]F_n = (m_2 - m_1)g[/itex].
     
  4. Jan 24, 2005 #3
    equilibrium

    The question "What is the normal force, FN, and what is the tension, T, in the rope? T (at t = 2.54s) = ______. At equilibrium: FN + T – m2 • g = 0. Then FN = _______." This is a timed simulation and at 2.54s the rope tension,T, is 9.789
     
  5. Jan 24, 2005 #4

    Doc Al

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    OK, now I see what you're talking about. Since T is given and equilibrium is assumed, your answer is correct; rounded off, the normal force would be 1.0 N.
     
  6. Jan 25, 2005 #5
    equilibrium

    Thanks for the quick reply.
     
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