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Autonomous ODE

  1. Jan 23, 2013 #1
    Hi everyone,

    Im looking for an autonomous first order ode that has the following properties.

    For dependent variable x:

    x(t=∞)=0

    x(t=-∞)=0

    and the function x(t) has one maximum.

    Any help would be great.

    Rgds...
     
  2. jcsd
  3. Jan 23, 2013 #2

    pasmith

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    This is impossible.

    Suppose the maximum is at [itex]t = t_0[/itex]. Then there exist [itex]t_1 < t_0 < t_2[/itex] such that [itex]x(t_1) = x(t_2)[/itex], but [itex]\dot x(t_1) = -\dot x(t_2)[/itex]. There is no way to express that requirement in an autonomous first order ODE.

    You are going to need a second-order autonomous ODE, as should be obvious from the fact that you want to satisfy two boundary conditions.
     
  4. Jan 24, 2013 #3
    What do you think of y' = - y^(3/2) ?
     
  5. Jan 24, 2013 #4
    Thanks pasmith

    Could you explain why it is not possible?
     
  6. Jan 24, 2013 #5
    Thanks JJ

    Is there an exact solution to this?
     
  7. Jan 24, 2013 #6
    dy/dx = -y^(3/2)
    dx = - dy/y^(3/2)
    x = (2 / y^(1/2)) +C
    y^(1/2) = 2/(x-C)
    y = 4/(x-C)²
     
  8. Jan 24, 2013 #7

    Mute

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    That has a divergence, not a maximum, though! I'm not sure that's what williamrand1 is looking for.

    williamrand1, what about trying to take a function that you know has the properties you desire, differentiate it, and then see if you can rewrite the derivative in terms of x(t), with no explicit time dependence?
     
  9. Jan 25, 2013 #8
    Hi williamrand1 !

    Then, what about this one :
    y' = -2y*sqrt(ln(1/y))
    which solution is : y = exp(-(x+c)²)
     
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