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A ball is dropped from 4 ft and rebounds back to 3 feet. If the ball was in contact with the ground for 0.01 seconds, then what is the average acceleration of the ball during contact? The answer on the back of the book is 3000 ft/sec^2. So average acceleration is defined as [tex] \frac{\Delta V}{\Delta t} [/tex]. So [tex] \frac{x}{0.01} [/tex]. Then [tex] \Delta V = 30 [/tex]. How would you get 30?
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