A 44 kg woman leaps vertically from a crouching position in which her center of mass is 48 cm above the ground. As her feet leave the floor her center of mass is 81 cm above the ground; it raises to 124 cm at the top of her leap.(adsbygoogle = window.adsbygoogle || []).push({});

What average force was exerted on her by the ground during the jump?

the initial force is the normal force (44 * 9.81) = 431.64 N

but i don't know what the final force is.

after i find the final force the average is (Fi+Ff)/2.

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# Homework Help: Average force and center of mass

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