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Average induced voltage

  1. Jul 25, 2011 #1
    1. The problem statement, all variables and given/known data

    A coil with 10 windings(radius 0,07m) is inside a homogenous magnetic(B=0,050T) field, it makes an angle of 90 degrees with the field lines so the magnetic flux is at it's max. Over a period of 0,050 seconds it gets turned by 180 degrees, what is the average induced voltage?

    2. Relevant equations

    phi=B*A
    Uinduced=-N* dphi/dt

    3. The attempt at a solution
    The area is 0.07²*pi= 0,015393804 m²
    So the magnetic flux in the situation before the turning is 0,015393804*0,050=0,0007696902 Wb
    (I dont normally write numbers like this)
    After it turns, this is the part i am unsure about, is the magnetic flux now -0,0007696902?
    because phi=B*cos(180)*A
    so the difference in magnetic flux is -2*(0,0007696902)
    Then Uinduced = -10 * (-2*(0,0007696902))/0.050 = 0,31 volts. Is this correct?

    I am verry sorry for my english. Thank you!
     
  2. jcsd
  3. Jul 25, 2011 #2
    Anyone? :-)
     
  4. Jul 25, 2011 #3

    Redbelly98

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    Welcome to Physics Forums.

    Yes, that looks good. I didn't check your arithmetic, but your procedure and reasoning are correct. The flux simply changes sign (+ to -) when the coil is flipped 180 degrees, so the change in flux is 2x the value of the flux.
     
  5. Jul 25, 2011 #4
    Thank you very much !
     
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