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Average Kinetic Energy of Gas

  1. Jun 24, 2016 #1
    1. The problem statement, all variables and given/known data

    Calculate the kinetic energy of CO, CO2, and SO3 at 276 K .

    2. Relevant equations

    KE = (3/2) RT
    KE= (1/2)(mass)(velocity)^2

    3. The attempt at a solution

    For CO:
    First attempt: KE=(3/2)(RT)=(3/2)(8.314 J/mol-K)(276K) = 3441.996 -- So that's wrong
    Second attempt:
    Relative Molecular Mass of CO= 28
    6.02x10^23 molecules of CO= 28g
    1 molecule of CO= 28/6.02x10^23
    4.65x10^-23g
    4.65x10^-26kg

    Kinetic energy of CO= 1/2(4.65x10^-26)(490^2)
    = 5.58x10^-21 J -- according to mastering this is also wrong


    Thank You
     
  2. jcsd
  3. Jun 24, 2016 #2

    Ygggdrasil

    User Avatar
    Science Advisor

    I believe this equation applies only to monatomic ideal gases. For molecules, such as CO, CO2, and SO3, you need to calculate the number of degrees of freedom for each of these molecules.
     
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