- #1
jegues
- 1,097
- 3
Homework Statement
Find the average power of the signal,
[tex]x_{1}(t) = 5cos(2\pi t + \frac{\pi}{10}) - 6sin(10t + \frac{\pi}{8})[/tex]
Homework Equations
The Attempt at a Solution
[tex]P_{avg} = \frac{1}{T_{1}} \int_{0}^{T_{1}} 25dt + \frac{1}{T_{2}}\int_{0}^{T_{2}}36dt[/tex]
[tex]P_{avg} = 61[/tex]
The answer they list is,
[tex]P_{avg} = \frac{61}{2}[/tex]
Why are they using the RMS value of the signal as the magnitude?