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Average power of a signal

  1. Oct 7, 2012 #1
    1. The problem statement, all variables and given/known data

    Find the average power of the signal,

    [tex]x_{1}(t) = 5cos(2\pi t + \frac{\pi}{10}) - 6sin(10t + \frac{\pi}{8})[/tex]

    2. Relevant equations



    3. The attempt at a solution

    [tex]P_{avg} = \frac{1}{T_{1}} \int_{0}^{T_{1}} 25dt + \frac{1}{T_{2}}\int_{0}^{T_{2}}36dt[/tex]

    [tex]P_{avg} = 61[/tex]

    The answer they list is,

    [tex]P_{avg} = \frac{61}{2}[/tex]

    Why are they using the RMS value of the signal as the magnitude?
     
  2. jcsd
  3. Oct 8, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    hi jegues! :smile:

    eg 25*cos*sin = (25/2)*sin2, so its average is 25/2 :wink:
     
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