# Average Power of a sled

1. May 14, 2007

### ssb

1. The problem statement, all variables and given/known data

A sled is being pulled along a horizontal surface by a horizontal force F of magnitude 600 N. Starting from rest, the sled speeds up with acceleration 0.08 m/s^2 for 1 minute.

Find the average power P created by force F.

2. Relevant equations

P = Fs/T

3. The attempt at a solution

So I need to first find displacement of movement. If y = .08x^2, then at 60 seconds y = 288 .... so displacement is 288 right?

The force is 600 N
so since P = Fs/T, then (600*288)/60 should be my answer right? Also would this answer be in watts? I know that 1 joule/second = 1 watt.

2. May 14, 2007

### neutrino

Apart from a tiny factor of 1/2, everything else is right. Yes, the SI unit of power is the Watt. Can you find where you missed the factor?

3. May 14, 2007

### ssb

So y = (1/2).08x^2

this would yield a displacement of 144
so then (600*144)/60

Also this answer is in joules so I need to multiply the whole thing by 60 to yield watts right?

so my final answer in watts should be 600*144 ????

4. May 14, 2007

### neutrino

As I said, there was nothing wrong with your first answer apart from that 0.5. It is Newtons.metre/second -> Joule/second -> Watt. Moreover, why would you take the trouble of first dividing and then immediately multiplying by 60?

5. May 14, 2007

### ssb

ack!

Thanks buddy! I appreciate the help!

6. Jul 15, 2007

### dawog

is power factor good or bad? Why?

Im just not sure!