(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If the rms voltage across the generator is 149 V, calculate the average power P(at 402 Hz) being used by the circuit.

R = 298 Ω, a capacitance C = 4.1 μF, inductance of L = 0.23 H

2. Relevant equations

V=IR

Avg power=Vrms*Irms(cos phase angle)

vrms=vmax/(sqrt 2)

Irms=Imax/(sqrt 2)

3. The attempt at a solution

Vrms=IrmsR

149/(sqrt 2)=Irms*298 I think that the 149 V given in the problem needs to be divided by 2 to get Vrms? is rms voltage across generator same as max voltage? i'm not exactly sure about that part...anyways I got:

Irms=.35355

Avg power= (.35355)(149/sqrt 2) cos (phase angle)

i solved for XL (581) and XC (96.6), which were both correct. so I got the phase angle to be 58.4 degrees

Avg power= (.35355)(149/sqrt 2) cos (58.4)

I'm not getting the right answer, so maybe my approach was wrong? Any help is appreciated.

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# Average power used by circuit?

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