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**1. Homework Statement**

find the result <x> (the expectation value) found when the position of a particle in the second (n=3) excited state of a rigid box.

**2. Homework Equations**

<x> = (2/a)[tex]\int[/tex]xsin

^{2}(xpi/a)dx

evaluated from 0 to a

**3. The Attempt at a Solution**

well when that integral is evaulated using the ground state the answer is a/2. I am not sure how they even got that. But my real problem is, is where does the n = 3 come in?

and where do I go from there?

thanks...