# Average speed

A person walks first at a constant speed of 5.01 m/x along a straight line from point A to B and then back along the line from B to A at a constant speed of 3.10 m/s

What is the average speed over the entire trip?

I've tried everything from adding the two and dividing by two. I've found that the avg. velocity over the trip is 0 m/s.
I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if thats even what you're suppose to do

## The Attempt at a Solution

tiny-tim
Homework Helper
welcome to pf!

hi frizzler43! welcome to pf! … I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if thats even what you're suppose to do

first, calculate the time for each half …

show us what you get Doc Al
Mentor
I just don't know how you are suppose to find the time o if thats even what you're suppose to do
Find the time to go from A to B, then the time to go from B to A. Add to get the total. Hint: Express the time in terms of the distance, which you can just call D.

how are you suppose to find the time?

tiny-tim
uhh? get on with it! 