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Average speed

  • Thread starter frizzler43
  • Start date
  • #1
A person walks first at a constant speed of 5.01 m/x along a straight line from point A to B and then back along the line from B to A at a constant speed of 3.10 m/s

What is the average speed over the entire trip?

I've tried everything from adding the two and dividing by two. I've found that the avg. velocity over the trip is 0 m/s.
I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if thats even what you're suppose to do

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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welcome to pf!

hi frizzler43! welcome to pf! :wink:
… I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if thats even what you're suppose to do
first, calculate the time for each half …

show us what you get :smile:
 
  • #3
Doc Al
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I just don't know how you are suppose to find the time o if thats even what you're suppose to do
Find the time to go from A to B, then the time to go from B to A. Add to get the total. Hint: Express the time in terms of the distance, which you can just call D.
 
  • #4
how are you suppose to find the time?
 
  • #5
tiny-tim
Science Advisor
Homework Helper
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how are you suppose to find the time?
uhh? :confused:

speed = distance/time …

get on with it! :rolleyes:
 

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