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Average speed

  1. Apr 8, 2016 #1
    1. The problem statement, all variables and given/known data

    image.jpg

    Ok so for part ii) b)

    I calculated the average speed as follow,
    Average speed= 3792.6/ (2x266.67), where 3792.6m is the total distance, and 266.67s is the time when v=0 , i.e. the time from O to the turning point

    But it should be 3792.6/ 400, where 400s is the time when x=0 , i.e. returns to O

    I'm confused, why isn't the total time (2x266.67) ? What is there a difference in the time?
     
  2. jcsd
  3. Apr 8, 2016 #2

    PeroK

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    Why do you think it takes as long to get back from the turning point as it does to reach it?
     
  4. Apr 8, 2016 #3

    BvU

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    Yes there is. v is not symmetric as with constant acceleration. Make a sketch.
     
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