rabbitweed said:mi/h is miles per hour. Think of it as distance/time, ie, velocity.
W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.
I hope it is clear then that the Weight force F = mW of the aircraft is
9.81 * 110000 = 1,079,100 N, or 1079 kN.
Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...
Let me know if there's anything you didn't get or would like clearing up:)
BlueOwl said:where does the 250 miles per hour come into the formula though? or it doesn't ?
Average thrust force is calculated by dividing the total thrust force produced by the airplane's engines by the total weight of the airplane, including fuel, passengers, and cargo.
The weight of the airplane, the type and number of engines, the air density, and the runway conditions can all affect the average thrust force during take-off.
Yes, the average thrust force can change during take-off as the airplane gains speed and lift. The engines may need to adjust their thrust to maintain a steady rate of acceleration.
Temperature affects air density, which in turn affects the amount of thrust needed for take-off. In warmer temperatures, the air is less dense and therefore the average thrust force may need to be higher to achieve the same level of acceleration.
No, the average thrust force for take-off varies depending on the type and size of the airplane, the number of engines, and the weight of the airplane. In general, larger and heavier airplanes will require more average thrust force for take-off.