- #1
in the rye
- 83
- 6
Hey everyone,
I am preparing for a Calc 2 lecture tomorrow with KhanAcademy videos. I was watching a video on average value of a function in which he said, basically, you'll have some definite integral on a to b divided by (b-a). My question is, is this essentially calculating average speed?
I was thinking of the graph of an integrand expressed in terms of a velocity-vs-time axis. By taking the integral we get a position function, but then we are dividing it by time. Since the integral is definite, the result would be that we have change in position/change in time. This would give distance/time, or average speed? Perhaps more specifically, average velocity. I'm just trying to understand this in a physical context.
Thanks.
I am preparing for a Calc 2 lecture tomorrow with KhanAcademy videos. I was watching a video on average value of a function in which he said, basically, you'll have some definite integral on a to b divided by (b-a). My question is, is this essentially calculating average speed?
I was thinking of the graph of an integrand expressed in terms of a velocity-vs-time axis. By taking the integral we get a position function, but then we are dividing it by time. Since the integral is definite, the result would be that we have change in position/change in time. This would give distance/time, or average speed? Perhaps more specifically, average velocity. I'm just trying to understand this in a physical context.
Thanks.