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Average value of function

  1. Apr 9, 2016 #1
    1. The problem statement, all variables and given/known data
    The average value of the function ##g(x) = 3^{\cos x}## on the closed interval ##[- \pi, 0]## is:

    2. Relevant equations


    3. The attempt at the solution

    I used the standard method for finding average value over an interval with my calculator using an integral, and got the answer 1.3528. However, the doesn't correspond to any of the possible answers given in my solutions book (30.980, 18.068, 7.593, 4.347, 0.849). What am I doing wrong? Could someone find thr average value and verify that I'm correct?
     
    Last edited: Apr 9, 2016
  2. jcsd
  3. Apr 9, 2016 #2
    It would help if you showed what you did.
     
  4. Apr 10, 2016 #3

    Samy_A

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    What @axmls said.

    Let me add a question. Are you sure you posted the exercise and the answers (yours and those from the book) correctly? Neither your answer nor the possible answers in the book is correct.
     
  5. Apr 10, 2016 #4

    Ray Vickson

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    Actually, the OP's answer is correct; Maple gets the average as 1.325276252 .
     
  6. Apr 10, 2016 #5

    Samy_A

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    Well, yes and no.

    That's why I asked the OP to check his post, including his own answer. He gave 1.3528 as answer, which probably is a typo.
    But without seeing anything of his calculations, I couldn't be sure. You are more generous. :oldsmile:
     
  7. Apr 10, 2016 #6

    Ray Vickson

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    OK: I see that I was not careful enough, and I had needed to clean my glasses.
     
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