- #1

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^{2}θ>=1/2 and <cos

^{2}θ>=1/2

How is the proof made?Integrate sin

^{2}θ from -Infinity to +Infinity?

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- Thread starter gennarakis
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- #1

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How is the proof made?Integrate sin

- #2

berkeman

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^{2}θ>=1/2 and <cos^{2}θ>=1/2

How is the proof made?Integrate sin^{2}θ from -Infinity to +Infinity?

You only need to integrate over one cycle. Every other cycle will be the same, right?

- #3

gb7nash

Homework Helper

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Average value on what interval?

- #4

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I just integrated from 0 to 2Pi changed sin^{2}θ=(1-cos2θ)/2 but the result is Pi and not 1/2...

- #5

berkeman

Mentor

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I just integrated from 0 to 2Pi changed sin^{2}θ=(1-cos2θ)/2 but the result is Pi and not 1/2...

You forgot to divide by 2*PI to get the average over the interval...

- #6

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Thanks!!It was my first answer on PF and I have to say it was fast and easy...:)

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