How do you find the average value in an experiment when all it consist of is weighing a beaker and adding 10 mL of water three times to it?
Math Is Hard said:I am not clear on the procedure. Before each weighing, do you start with an empty beaker and then add 10 mL of water to it? Or do you add more water to the water from the previous weighing each time?
Math Is Hard said:That is a very odd exercise. At first I thought it was to demonstrate the margin of human error that you might encounter when weighing the same amount of a substance during consecutive trials, but I am not sure what this is trying to teach.
If you only want an average of the water weights I assume it is
(total weight - beaker weight) for each of the three weighings, summed up and divided by total number of weighings (3), but I better back off here because there might be someone who is more familiar with this exercise.
Did the teacher give any hints about what this would demonstrate?
ok, do you know how to compute an average (a mean?)President Mercury said:Well I figured the average value would be the weight of the beaker empty. Since that is the original state it is in. I don't think that I have to consentrate on the 10mL part and I probably shouldn't have mentioned it. I know this is vague but if the average value isn't given then where else could it come from except for any original state.
Math Is Hard said:ok, do you know how to compute an average (a mean?)
Math Is Hard said:yes, you can also compute a "standard deviation" from your weighings. Now is this a chemistry class or a statistics class?