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Average velocity of hiker

  1. Sep 25, 2011 #1
    1. The problem statement, all variables and given/known data

    a hiker walks 6.7 miles to the east in 5.1 hours. then turns around and walks 1.1 miles to the west in 1 hour. what was her average velocity during the trip?
    A 1.2mph
    B 1.3mph
    C .92mph
    D 3.9mph

    2. Relevant equations
    not sure how to write what i used


    3. The attempt at a solution
    6.7/5.1=1.3
    1.1/1=1.1
    1.3+1.1=2.4/2=1.2
     
  2. jcsd
  3. Sep 25, 2011 #2

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    It seems you're not done yet! :smile:

    Let's start with the word "velocity".
    Do you know what it means?
    That is, is it a scalar or a vector?

    Second, the term "average velocity".
    What you should know is that you shouldn't average the speeds of the first part and the second part.
    Instead you should calculate the total distance and divide that by the total time.
     
  4. Sep 25, 2011 #3
    velocity is a vector because it has a magnitude and a direction.
    so i should do something like 6.7+1.1/5.1+1=7.8/6.1=1.27
     
  5. Sep 25, 2011 #4

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    You just got the "average speed".
    To get the "average velocity" you need to take into account that the second part of the trip is back.

    (And please add parentheses when they are required. :wink:)
     
  6. Sep 25, 2011 #5
    okay so how do i do that??
     
  7. Sep 25, 2011 #6

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    Going back is "minus" vector wise.
     
  8. Sep 25, 2011 #7
    so should i do 6.7-1.1/5.1+1
     
  9. Sep 25, 2011 #8

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    Shall we make that: (6.7-1.1)/(5.1+1)?
    The parentheses are really required.
    Otherwise you're quite right.
     
  10. Sep 25, 2011 #9
    okay. i got why the () are required. haha thanks i think im almost done
     
  11. Sep 25, 2011 #10

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    Yeah, I think so too...
     
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