1. The problem statement, all variables and given/known data A train at a constant 42.0 km/h moves east for 33 min, then in a direction 64.0° east of due north for 25.0 min, and then west for 69.0 min. What are the (a) magnitude (in km/h) and (b) angle (relative to north, with east of north positive and west of north negative) of its average velocity during this trip? 2. Relevant equations The way I inturpreted the problem I needed to first find the time in hours and the displacement in kilometers for each vector then I added the displacements over the times. here is the work I did. 3. The attempt at a solution First I calculated the total time. Since time isn't a vector I added everything. 33'*/60'=.550h 25'*/60'=.417h 69'/60'=1.15h Sum = 2.12h Next I found the total distance 42km/h*.550h=23.1km 42km/h*.417h=17.5km 42km/h*1.15h=48.3km then I added the magnitudes of the three vectors taking the magnitude of the x coordinate for the second r=(23.1km)+(17.5km *Cos(26))-(48.3km)= -9.47 Finally I divided displacement over time to get an unconvincing and completely wrong answer of -4.47 What did I do wrong.