- #1
VenaCava
- 20
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When calculating an average velocity in a problem containing multiple velocities each occurring for different lengths of time, would I be correct in calculating the total displacement and then dividing by the total time?
For example:
Suzy goes for a jog one day. She runs at an average velocity 3 m/s north for 2 minutes and then an average velocity of 5m/s south for 3 minutes. What is her average velocity?
I believe it would be solved like this:
d=vt = (3m/s)(120s) =360m
d=vt = (-5m/s)(180s)=-900m
total d = 360m + (-900m) =-540m
total t =300s
Average V = -540m/300s = -1.8m/s
Thank you.
For example:
Suzy goes for a jog one day. She runs at an average velocity 3 m/s north for 2 minutes and then an average velocity of 5m/s south for 3 minutes. What is her average velocity?
I believe it would be solved like this:
d=vt = (3m/s)(120s) =360m
d=vt = (-5m/s)(180s)=-900m
total d = 360m + (-900m) =-540m
total t =300s
Average V = -540m/300s = -1.8m/s
Thank you.