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## Homework Statement

A car undergoes a displacement of 1200m @ 90degrees, follow by another displacement of 900m @ 0degress.

Calculate the average speed for the whole trip and the time to return to the starting point in the shortest possible distance at 20.0m/s

## Homework Equations

Avg speed would be total displacement/total time

2100m/210s=10.0 m/s, which is not right, it should be 12.7m/s and I don't know how to arrive at that figure?

The time for the second equation should be 75.0s. How do I get there?

If the total time that I have for the whole trip is 210s? Is that even the correct time?