# Avg Velocity and Avg Speed

doing this problem 400km East in .75 hrs from a to b and 960 km south in 1.5 hrs from b to c.
Ang Velocity is /Delta x divided by /delta t correct?
and avg speed is just adding the distance's and times and diving by the time right?
Well for the avg velocity for this problem its saying its wrong any help?

Mentor
Show exactly what you did. To find the average velocity, start by finding the displacement.

found displacement by using a right-hand coordinate system. and did solved by doing a^2 + b^2 = c^2. got the displacement to be 1040 km for the total trip. (Checked it its right)
Did velocity avg by 960-400/1.5-.75 = 747 and it says its wrong...

Mentor
found displacement by using a right-hand coordinate system. and did solved by doing a^2 + b^2 = c^2. got the displacement to be 1040 km for the total trip. (Checked it its right)
You found the correct displacement, now use it to find the average velocity.
Did velocity avg by 960-400/1.5-.75 = 747 and it says its wrong...
I have no idea what you are calculating here. What happened to the displacement that you just calculated? That's what you need to use.

well it said change in x over change in t
960 and 400 was the two distances, how to apply the displacement? do i subtract from that?!

Mentor
Average velocity is just displacement divided by time. Do it!