- #1

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Ang Velocity is /Delta x divided by /delta t correct?

and avg speed is just adding the distance's and times and diving by the time right?

Well for the avg velocity for this problem its saying its wrong any help?

- Thread starter badtwistoffate
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- #1

- 81

- 0

Ang Velocity is /Delta x divided by /delta t correct?

and avg speed is just adding the distance's and times and diving by the time right?

Well for the avg velocity for this problem its saying its wrong any help?

- #2

Doc Al

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Show exactly what you did. To find the average velocity, start by finding the displacement.

- #3

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Did velocity avg by 960-400/1.5-.75 = 747 and it says its wrong....

- #4

Doc Al

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You found the correct displacement, nowbadtwistoffate said:found displacement by using a right-hand coordinate system. and did solved by doing a^2 + b^2 = c^2. got the displacement to be 1040 km for the total trip. (Checked it its right)

I have no idea what you are calculating here. What happened to the displacement that you just calculated?Did velocity avg by 960-400/1.5-.75 = 747 and it says its wrong....

- #5

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960 and 400 was the two distances, how to apply the displacement? do i subtract from that?!

- #6

Doc Al

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Average velocity is just displacement divided by time. Do it!

- #7

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but what does my schaums outline says change in x over change in timee, im confused :(

is it displacement over change in time or total time?

also isnt displacement delta x?

is it displacement over change in time or total time?

also isnt displacement delta x?

Last edited:

- #8

Doc Al

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