Ax^2-40x+40=0 homework problem help

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  • #1
dbn
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if you can solve ax^2-40x+40=0 for a and x that would be great
 

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  • #2
AKG
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No. We have two unknowns (a and x) and one equation. At best, we can express a in terms of x, and vice versa, but no better. To express x in terms of a, simply apply the quadratic formula to the equation you have. You'll get:

[tex]x = \frac{20 \pm 2\sqrt{10(10 - a)}}{a}[/tex]
 
  • #3
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if you can solve ax^2-40x+40=0 for a and x that would be great
use this formula [tex]\frac{-b ^+_- \sqrt{b^2 - 4ac}}{2a}[/tex]where a=a, b=-40 and c=40

Paden Roder
 
  • #4
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Well, sorry! I just stated the quadratic formula, as AKG said. This was the first time I have used LaTeX though, pretty cool, once you get the hang of it.

Paden Roder
 
  • #5
dbn
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i still don't get it can some one give me a walk through on how to use them with this problem/
 
  • #6
dbn
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a= 0 x= 1
i just fount it
 
  • #7
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*groan*

I bet there are millions of answers for this one.

I came up with a = 10, x = 2
 
  • #8
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phreak said:
I bet there are millions of answers for this one.
:uhh:

I bet there's more than that. In fact, I bet the set of all possible answers is uncountably infinite. I'd bet a lot of money on it, since, as AKG said, with one equation and two unknowns, this isn't going to go anywhere.
 
  • #9
arildno
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dbn said:
i still don't get it can some one give me a walk through on how to use them with this problem/
Now, while the others have shown how to find x given a, here's how you may find the a-value for any choice of x-value:
[tex]ax^{2}-40x+40=0[/tex]
Rewrite this as:
[tex]a=40\frac{x-1}{x^{2}}[/tex]

Hence, for any non-zero choice of x, only a single value for a is allowed by the equation.
 
  • #10
Is this the whole question?
Unless it's an 'express x in terms of a' type question you can't solve it with only that information.
 

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