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Azimuth Calculation

  1. Dec 6, 2015 #1
    1. The problem statement, all variables and given/known data
    In the attachment. Need to calculate azimuth of BC.

    2. Relevant equations


    3. The attempt at a solution
    I dont understand why the azimuth of AB would be given as 126 degrees when it is almost a complete revolution of 360 degrees. I calculated the back azimuth which would be 306°55'17''. (126°55'17"+180°=306°55'17'').I added the interior B angle and got 178°18'58". But how could the of BC be greater then AB? Please help me. Thanks!
     

    Attached Files:

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  2. jcsd
  3. Dec 6, 2015 #2
    There is a B arc labelled angle B and then there is a wider arc around that B arc. That wider arc is completely deceptive.

    The 126 55 17 is a bearing from N.
     
  4. Dec 6, 2015 #3
    Thanks for replying. Does that mean my answer is correct?
     
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