remember that H and B are not the same.radiator said:I used ([tex]\nabla[/tex] X E ) = -dB/dt , and then integrated that expression with respect to t , for some reason I am getting an incorrect answer ?!
The Attempt at a Solution
the correct answer is H = 0.4 w*(eps) *cos([tex]\omega[/tex]t-50x) [tex]\widehat{z}[/tex]
The B-Field and E-Field are both components of the electromagnetic field. The E-Field, also known as the electric field, is produced by electric charges and exerts a force on other electric charges. The B-Field, also known as the magnetic field, is produced by moving electric charges and exerts a force on other moving electric charges.
The B-Field can be calculated from the E-Field using the formula B = (u/ε) * E, where u is the permeability of the medium and ε is the permittivity of the medium. The units for B-Field are Tesla (T) or Gauss (G) and the units for E-Field are Volts per meter (V/m).
No, the B-Field and E-Field are always present together and are interconnected. Changes in one field can cause changes in the other field.
Finding the B-Field from the E-Field helps us understand and predict the behavior of electromagnetic waves, which are essential for many technologies such as communication systems, medical imaging, and energy production.
Yes, there are many real-life applications of finding the B-Field from the E-Field. Some examples include MRI machines, particle accelerators, and electric motors. Understanding the relationship between these fields also helps in the development of new technologies and advancements in existing ones.