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Hi

I am trying to find the average of a throw in backgammon with two dice. Recall that two dice with the same amount of eyes (is that how one say it in English?) count double. What I have is

[tex]

\frac{{2 \cdot 3 + 3 \cdot 4 + 4 \cdot 5 + 4 \cdot 6 + 6 \cdot 7 + 5 \cdot 8 + 4 \cdot 9 + 2 \cdot 10 + 2 \cdot 11 + 1 \cdot 16 + 1 \cdot 20 + 1 \cdot 24}}{{36}}

[/tex]

The integer to the right of the multiplication-sign is the throw, and the integer to the left is the different ways of achieving it. I get 8.17

Can you confirm my answer? It seems high

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# Homework Help: Backgammon math problem

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