1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Badly need help on physics problem

  1. Oct 28, 2009 #1
    1. The problem statement, all variables and given/known data
    The system shown in Figure 4.54 has an acceleration of magnitude 1.20 m/s2, where m1 = 3.70 kg and m2 = 7.60 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines.

    http://www.webassign.net/serpop/p4-54alt.gif

    (a) Find the coefficient of kinetic friction.
    (b) Find the tension in the string.


    3. The attempt at a solution

    ive tried to compile all the forces into one equation and it turned out like this:

    Fk on m1 + Fk on m2 + Fg m1 - Fg m2 = Fnet
    n1*muk + n2*muk + m1g - m2g = m2a

    -please i need help as fast as possible
     
  2. jcsd
  3. Oct 28, 2009 #2

    Delphi51

    User Avatar
    Homework Helper

    The angle matters. You shouldn't have m1g and m2g, but rather the components of those forces that are along the slope. The n1 and n2 will also be components of the mg forces, so they'll have sin 35 or cos 35 in their expressions, too.

    Welcome to PF!
     
  4. Oct 28, 2009 #3
    ya i know. sorry i didnt type it in more detail cause i was late for another class. if i added the numbers to it, it came out

    7.6*9.8*cos35*muk +3.7*9.8*sin35 + 3.7*9.8*cos35*muk - 7.6*9.8*sin35 = 9.12

    -please tell me if i'm missing anything or if my numbers are off. thank you for the fast responses
     
  5. Oct 28, 2009 #4

    Delphi51

    User Avatar
    Homework Helper

    For the ma on the right, your number doesn't seem right.
     
  6. Oct 28, 2009 #5
    i multiplied the acceleration given and the mass of m2 because its the block pulling the the other. i tried adding m1 and m2 together and using that for the net force but i still go the answer wrong
     
  7. Oct 28, 2009 #6

    Delphi51

    User Avatar
    Homework Helper

    ma = (3.7 + 7.6)*1.2 = 13.56
    I'd say the signs on the left side are all wrong. Friction should be negative.
     
  8. Oct 28, 2009 #7
    ok so I've got

    7.6*9.8*sin35 - 7.6*9.8*cos35*muk - 3.7*9.8*sin35 - 3.7*9.8*cos35*muk) = 13.56

    when i factor out the muk n balance out the equation i get muk = 0.0919. is that what you got? sorry i'm being really picky about this but i have to make sure because this is my last attempt on this problem. i'm really grateful for all the help
     
  9. Oct 28, 2009 #8

    Delphi51

    User Avatar
    Homework Helper

    I actually got .0924, but I use g=9.81 so we probably agree.
     
  10. Oct 28, 2009 #9
    ok it was right. thank you so much. now i have to do work on getting tension on the string. im not too sure how to start it. i kind of tried mixing the components around to make it

    (m2g - n2muk) + (m1g + n1muk) = T

    but my answer ends up being 60.6N and i'm very sure thats not right.
     
  11. Oct 28, 2009 #10

    Delphi51

    User Avatar
    Homework Helper

    Recommend you concentrate on just m1. The sum of the forces parallel to the ramp equals ma.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Badly need help on physics problem
Loading...