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**frfr1. Homework Statement**

A 15 kg uniform wooden board of length L is balanced at its center. A 6 kg object is to be placed on the right end. How far from the balance point must a 9 kg object be placed to keep the board in equilibrium?

## Homework Equations

##m_1d_1 = m_2d_2##

## The Attempt at a Solution

Is it just ##6 \frac{L}{2} = 9 d_2##

##d_2 = \frac{L}{3}##? I guess I am not sure since they mention the weight of the wooden board, but since it is uniformly distributed, its weight shouldn't matter?