1. The problem statement, all variables and given/known data Copper (II) Chloride dihydrate is mixed with solid aluminum. Find the products and balance the equation. 2. Relevant equations N/A 3. The attempt at a solution The original equation that I got was: CuCl2 ∙ 2H2O + Al --> AlCl3 + Cu + H2O When I balanced it, I got: 3 CuCl2 ∙ 2H2O + 2 Al --> 2 AlCl3 + 3 Cu + 2 H2O but I'm unsure about that. I am just wondering if the H2O at the end of the equation should have a coefficient of 6 because 3 [CuCl2 ∙ 2 H2O] were needed. So then the equation would be: 3 CuCl2 ∙ 2H2O + 2 Al --> 2 AlCl3 + 3 Cu + 6 H2O instead? I do not know which one is correct. Please help me!
Should be 6. Note that CuCl_{2}^{.}2H_{2}O is equivalent to CuCl_{2}(H_{2}O)_{2} or even CuCl_{2}H_{4}O_{2}.