Copper (II) Chloride dihydrate is mixed with solid aluminum. Find the products and balance the equation.
The Attempt at a Solution
The original equation that I got was:
CuCl2 ∙ 2H2O + Al --> AlCl3 + Cu + H2O
When I balanced it, I got:
3 CuCl2 ∙ 2H2O + 2 Al --> 2 AlCl3 + 3 Cu + 2 H2O
but I'm unsure about that. I am just wondering if the H2O at the end of the equation should have a coefficient of 6 because 3 [CuCl2 ∙ 2 H2O] were needed. So then the equation would be:
3 CuCl2 ∙ 2H2O + 2 Al --> 2 AlCl3 + 3 Cu + 6 H2O instead?
I do not know which one is correct. Please help me!