Mastering Equation Balancing in Chemistry: A Universal Method for All Reactions

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In summary: H20 + 6CO2This is where it gets tricky, because we now have 10 HYDROGEN on the RIGHT and 13 OXYGEN on the LEFT. We need to find a way to combine these two sets of 13 OXYGEN so that we have the same number on both sides. There are a few ways to do this, but the easiest way is to add them together: C4H10 + (13/2)O2 => H20 + 6CO2So
  • #1
ampakine
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I'm in my 3rd year of a chemistry course so its fairly ridiculous that I can't balance equations. I can balance simple equations in my head in seconds but what I need is an algorithm that I can use to balance any equation I will ever encounter. Can any of you teach me a method for balancing equations that I will be able to apply to all reaction equations that I ever come across in chemistry?
 
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  • #2
ampakine said:
I'm in my 3rd year of a chemistry course so its fairly ridiculous that I can't balance equations. I can balance simple equations in my head in seconds but what I need is an algorithm that I can use to balance any equation I will ever encounter. Can any of you teach me a method for balancing equations that I will be able to apply to all reaction equations that I ever come across in chemistry?

There is no one size fits all approach. You just need to do many problems to gain experience. Sometimes a bit of trial and error is involved. Try this out.

Butane undergoes complete combustion to yield carbon dioxide and water:

C4H10 + O2 => H20 + CO2

Can you balance this?
 
  • #5
c03rcion said:
C4H10 + O2 => H20 + CO2

Can you balance this?

No. In my summer exams I had a Hess' Law question that I couldn't even start because I couldn't balance the equation for the combustion of acetaldehyde.

EDIT: I looked it up and I see now that when I have trouble balancing 1 element like that I just put a fraction beside it then multiply everything by what's under the fraction. Knowing that should make things a whole lot easier for me from now on. I woulda had no trouble with that Hess' Law question if I just knew how to balance that equation lol.
 
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  • #6
Ok the only way you will learn to balance equations is to practice by doing problems. There is no silver bullet, there is no algorithm, you just have to practice over and over. If you can't balance equations, you won't get far in chemistry (I think you are aware of this). Look in your general chemistry textbook and work problems. Look on google for practice problems. Do whatever you have to do to learn this.

And by the way, expect a little trial and error with these problems.

Ok let's look at the combustion of butane:

C4H10 + O2 => H2O + CO2

ON THE LEFT SIDE of the equation we have:
4 atoms of CARBON
10 atoms of HYDROGEN
2 atoms of OXYGEN

ON THE RIGHT SIDE of the equation we have:
2 atoms of HYDROGEN
1 atom of CARBON
3 atoms of OXYGEN

I'll start by balancing CARBON on BOTH sides of the equation:
C4H10 + O2 => H2O + 4CO2

**so now we have 4 CARBON atoms on both sides, but have 2 atoms of OXYGEN on the LEFT and 9 OXYGEN on the RIGHT

Balancing the OXYGEN on BOTH sides:
C4H10 + (9/2)O2 => H2O + 4CO2

**so now on the LEFT we have 9 OXYGEN (because 9/2 X 2 = 9) and on the RIGHT we have 9 OXYGEN (1 + 8 = 9)

now we have to balance the HYDROGEN on both side:

C4H10 + (9/2)O2 =>

5H2O + 4CO2

**so now we have 10 HYDROGEN on each side. But we have a problem, on the RIGHT we have 13 OXYGEN on the RIGHT side and on the LEFT we have 9 OXYGEN.

this next step is really important: DON'T FREAK OUT!

Adding 13 OXYGEN to the LEFT:
C4H10 + (13/2)O2 =>

5H2O + 4CO2

So now we look at our equation:

LEFT SIDE: 4 CARBON, 10 HYDROGEN, 13 OXYGEN
RIGHT SIDE: 4 CARBON, 10 HYDROGEN (5 x 2 = 10), 13 OXYGEN (5 + ((4 x 2)) = 13)

So the law of conservation of mass is satisfied.


If you have any chemistry questions please ask me. You can send me private messages. I am trying to do good things with my life and this chemistry degree I spend so much money on so please ask for help, it makes me feel good to share information.
 
  • #7
c03rcion said:
there is no algorithm

Not true. Algorithm exists and was even already mentioned in this thread. How do you think equations are balanced by programs like Equation Balancing and Stoichiometry calculator? Algorithmically, using algebraic method. Whether this method is suited for manual balancing is a completely different problem.

the only way you will learn to balance equations is to practice by doing problems

Agreed. For a training in balancing equations go to

http://www.chemistry-quizzes.info/

You will need to register (for free), then there are several hundred practice problems, grouped into easy, hard, insane and redox. After logging you just select a section from the main page - and try.
 
  • #8
Thanks c03rcion. What I was struggling with was balancing the oxygens at the end, I didn't think of using a fraction to balance it then multiplying every coefficient by the denominator of the fraction. I've been practicing a fair bit and now I have no trouble with these combustion equations. I'm going to look for some worst case scenario equations and see if I can balance them with this method. That algebraic method Borek mentioned does look like its a silver bullet algorithm but its pretty complicated, I haven't figured out how to use it yet. I send you a PM c03rcion. Right now I badly need some assistance with physical chemistry related fields.
 
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  • #9
Please note: by forum rules PMs should be not used for asking for help.

Apart from the fact that someone may not want to get such PMs (not the case here), it is better to make your questions visible to everyone, this way you may get an answer much faster, as you don't rely on this one, particular person. Besides, in the case someone trying to help is wrong, if others watch the thread they have a chance to correct the mistake.
 
  • #10
Yeah I'll post the questions in the forums anyway, that way I'll get explanations from more than 1 person. Borek that's a brilliant site you started there. I was thinking about making a site like this for a long time but didn't have the time to get it started. If you need any help I'm fairly experienced with PHP, SQL and javascript and have put a lot of thought into how to build online chemistry learning tools. For example I can contribute new questions and write the scripts for dealing with them. I can't post on the forum for some reason though. I don't see any reply or new thread buttons.
 
  • #11
ampakine said:
I can't post on the forum for some reason though. I don't see any reply or new thread buttons.

I see you tried reaction balancing. Have you checked if you can post AFTER trying to answer the questions?

Edit: OK, I see you already posted. Forum was extensively spammed by bots, now - to be able to post - you need to try to answer at least one question. It works :smile:
 
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1. What is the purpose of balancing reaction equations?

The purpose of balancing reaction equations is to ensure that the number of atoms of each element is the same on both sides of the equation. This is necessary because in a chemical reaction, atoms are neither created nor destroyed, they are simply rearranged.

2. How do you balance a chemical equation?

To balance a chemical equation, you must add coefficients in front of each molecule to ensure that the number of atoms of each element is equal on both sides of the equation. You may also need to adjust the subscripts of the molecules to maintain the correct ratio of elements.

3. Is there a specific order in which the elements or molecules should be balanced?

There is no specific order in which elements or molecules should be balanced. However, it is often helpful to start with elements that appear in only one molecule on each side of the equation, and then move on to more complex molecules.

4. What do you do if a reaction has an odd number of atoms of an element on one side of the equation?

If a reaction has an odd number of atoms of an element on one side of the equation, you can multiply all of the coefficients by 2 to make the number of atoms even. Then, continue balancing the equation as usual.

5. Can you balance a reaction equation without changing the chemical properties of the substances involved?

Yes, balancing a reaction equation does not change the chemical properties of the substances involved. The coefficients we add only change the number of molecules involved in the reaction, not the actual substances themselves.

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