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## Homework Statement

A 0.478-kg ball is thrown at a 22.3-cm tall, 0.383-kg object and hits with a perfectly horizontal velocity of 12.8 m/s. Suppose the ball strikes at the very top of the object. After collision the ball has a horizontal velocity of 4.6 m/s in the same direction. The object now has an angular velocity of 1.63 rad/s. If the object's center of mass is located 15.6 cm below the point where the ball hits, what is the moment of inertia of the object?

## Homework Equations

I = MR^2

## The Attempt at a Solution

I am honestly not sure where to begin on this one. I know the initial momentum is conserved and is proportional to the ball's mass and initial velocity. I was sick for the lecture and would appreciate any help on how to solve this problem.

Thanks