A single charge q1 = 1.10E-7 C is fixed at the base of a plane that makes an angle theta with the horizontal direction. A small ball of mass m = 1.75 g and a charge q2 = 3.30E-8 C is placed into a smooth frictionless groove in the plane that extends directly to the fixed charge (image attached.) It is allowed to move up and down until it finds a stable position d = 11.0 cm from the fixed charge. What is the value of theta (t)?
Fe = kq1q2/d^2
Fg = mg
The Attempt at a Solution
Fe = (8.99E9)(1.1E-7)(3.3E-8)/(0.11^2) = 0.002697 N [up to the right]
Fg = (.00175)(9.8) = 0.01715 N [down]
(Fe)(sin(t)) = mg
(0.002697)(sin(t)) = 0.01715
sin(t) = 6.358917316
Since sin(t) has to be between -1 and 1 it is impossible to find t.
Any help detecting my problem would be greatly appreciated.