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Ball from a cliff

  1. Jul 27, 2009 #1
    A girl at the bottom of a [tex]100\ m[/tex] high cliff throws a tennis ball vertically upwards. A boy at the very top of the cliff drops a golf ball so that it hits the tennis ball while both balls are still in the air. The acceleration of both balls can be assumed to be [tex]10ms^{-2}[/tex] downwards.

    With what speed is the tennis ball thrown so that the golf ball strikes it at the top of its path?

    I don't know where to start with this one. Is the question missing something? I assume that both balls were both released at the same time...

    Any help would be great.

    Thanks
     
  2. jcsd
  3. Jul 27, 2009 #2
    for the tennis ball: v = vi + at
    0 = vi -10t
    (1) write an equation with t = ....

    for the golf ball: d=vi x t + (at^2)/2
    vi = 0 (for the golf ball) a = 10 and substitute the t from equation (1)

    you'll end up with (2) d = ....

    for the tennis ball: 100 - d = vi x t + (at^2)/2
    a = -10, substite equation (2) for d, and substitute (1) for t

    gudluck and tell me waht the answer is
     
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