# Ball hit with racket

1. Oct 12, 2008

1. The problem statement, all variables and given/known data
A 116 g ball is traveling to the left with a speed of 34 m/s when it is struck by a racket. The force on the ball, directed to the right and applied over 21 ms of contact time, is shown in the graph. What is the speed of the ball immediately after it leaves the racket?

this graph comes with it
http://www.webassign.net/grr/p7-16.gif

2. Relevant equations
I know it has something to do with impluse so I = F x T

3. The attempt at a solution
i have no idea!

2. Oct 12, 2008

### Rake-MC

try $$F\Delta t = m\Delta v$$

area under the graph = impulse, divide by mass = velocity

3. Oct 12, 2008

### Mentallic

Yes, that formula is needed since $$I=\Delta \rho$$ where $$\Delta \rho$$=change in momentum.
All you need to do to find the impulse is calculate the area under the graph.