- #1

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I first find the initial velocity in x-direction: 12.5 m/s. Then I use energy conservation in z-direction to find an expression for the max height of the ball: v^2(initial in z-direction)/(2g)

This equals v(initial in z-direction)*t + (1/2)a*t^2.

But I don't get the correct answer. Where's my mistake?