1. The problem statement, all variables and given/known data A 1.60 kg, horizontal, uniform tray is attached to a vertical ideal spring of force constant 200 N/m and a .3 kg metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down .149 meters below its equilibrium point to a point A and released from rest. At approximately .242 meters above point A the ball will lose contact with the spring, find the time this happens and the velocity of the ball at that time. 2. Relevant equations x=Acos(w*t) Fx=-200*x-9.8 3. The attempt at a solution There was an earlier part of the question where you were supposed to find the height at which the ball leaves the tray and I thought that I could derive the time from that equation but I wasn't able to. As for the velocity I tried taking the second integral of the acceleration, but that also led me to the wrong answer.