- #1
jhson114
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A ball with mass m = 1 kg is attached to a string of length l = 1 m. The other end of the string is attached to a hook in the ceiling a height H = 2.5 m above the floor. The ball is originally positioned so that the string is parallel with the ground. The ball is now released from rest. As the ball falls, the tension in the string increases until it breaks at an angle q = 24 degrees with the ceiling. What is the tension when the string breaks.
From my understand tension on a pendulum is mgcos(angle), but i keep getting the wrong answer. so i tried a different way, where you find the initial total energy, minus potential energy at 24 degrees to get the kinetic energy. using the kinetic energy equation you get the velocity at angle 24 degrees. using the velocity, i used the centripetal force equation F=m(v^2/r), but this answer is also wrong. please help. thank you
From my understand tension on a pendulum is mgcos(angle), but i keep getting the wrong answer. so i tried a different way, where you find the initial total energy, minus potential energy at 24 degrees to get the kinetic energy. using the kinetic energy equation you get the velocity at angle 24 degrees. using the velocity, i used the centripetal force equation F=m(v^2/r), but this answer is also wrong. please help. thank you