1. The problem statement, all variables and given/known data A ball is projected horizontally from the edge of a table that is 0.443 m high, and it strikes the floor at a point 1.84 m from the base of the table. The acceleration of gravity is 9.8 m/s^2 2. Relevant equations a) What is the initial speed of the ball? Answer in units of m/s b) How high is the ball above the floor when its velocity vector makes a -18.9486 degree angle with the horizontal? Answer in units of m. 3. The attempt at a solution a) i got it right, and the answer is 6.13 b) this is what i have trouble on. I started by finding Vy using (6.13)(tan -18.9486)=Vy and i got: Vy=-2.10 I then used the formula Vf = Vo + a*t to get time. I got t=-.21 s Next i used d = Vot + 0.5a*t^2 to solve for distance and i got d= .22 Finally i did 0.443-0.22 and i got 0.22. The answer is not .22. I need help please. What did i do wrong?