The image above shows a basketball (a thin spherical shell I=⅔ mR^2) rolling don an incline of height 8.4 m. If the ball is already rolling with an initial linear speed of 3.0 m/s then what will be the final linear speed when it rolls off the incline?
I = 2/3 m R^2
KE = 1/2 m v^2 + 1/2 I ω^2
ω = v / R
PE = m g h
The Attempt at a Solution
I know that i am missing some equations but honestly i don't know where to start other than substituting for ω and I.
KE = 1/2 m v^2 + 1/2 (2/3 m R^2) [(v / R)^2]
i do not think that i need the potential energy equation, but i mentioned it just incase. Also, how do i cancel out the mass and radius since they are not given in the problem?