1. The problem statement, all variables and given/known data A ball of mass 2.30 kg and radius 0.142 m is released from rest on a plane inclined at an angle q = 42.0° with respect to the horizontal. How fast is the ball moving (in m/s) after it has rolled a distance d=1.35 m? Assume that the ball rolls without slipping, and that its moment of inertia about its center of mass is 1.70E-2 kg·m2. 2. Relevant equations .5mv^2+.5I(v^2/R^2) = mgdsin(angle) 3. The attempt at a solution I plugged in the numbers to equation above and got 3.2 m/s by solving for v...am I doing something wrong, because it is not the right answer?!?