A ball is thrown with an initial speed of 31 m/s at an angle of 45°.The ball is thrown from a height of 10 m and lands on the ground. (a) Find the time of flight. I used the following formula: Yf = Yo + VoT - (1/2)GT^2 0 = 0 + (31 m/s sin 45)T - (1/2)(9.8 m/s^2)T^2 0 = 21.92T - 4.9T^2 -21.92T = -4.9T^2 T = 4.47s I'm checking my answer for the problem on my school website and it's coming back as wrong. I pretty sure I'm using the correct formula for problem. The math looks right.