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**Question:**

How long does it take the ball to reach the cliff?

**0.82s**

Neglecting air resistance and the height of the man, calculate the height above the base of the cliff at which the ball hits.

**1.66m**

How fast is the ball moving when it reaches the cliff?

**37.3m/s**

Here is where I am having trouble...

At what time does the ball reach its largest vertical height?

I am sure that I have to find the intitial vertial velocity:

31 = 38cos(x)(0.82) where x is the angle x = 5.8 degrees

vy0 = 38sin(x) vy0 calculated to be 3.84

vf = v0 + at

0 = 3.84 + (-9.8)t = 0.39s

time to max height i figured to be 0.39s

This is the incorrect answer, what did I do wrong? Any suggestions?

Thanks!