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Ballistic cart simple physics

  1. Sep 30, 2011 #1
    Hi,
    I've tried to figure this out but I just can't! Please help me understand how to work it out???

    A ballistic cart is a wheeled cart that can launch a ball in a direction perpendicular to the way the cart moves and can then catch the ball again if it falls back down on the cart. Holding the cart stationary on a horizontal track, you confirm that the ball does indeed land in the cart after it is launched. Let’s say that the cart launches the ball with an initial velocity of 5.50 m/s up relative to the cart while the cart is rolling with a constant velocity of 7.00 m/s to the right. Using g = 10.0 m/s2, and neglecting air resistance, determine

    (a) the time it takes the ball to return to the height from which it was launched.

    (b) the magnitude of the displacement of the cart during this time.

    Thank you!!!
     
  2. jcsd
  3. Oct 1, 2011 #2
    part (a) is simply the total time of flight, i.e find the time until max height and then double it for the full trajectory. Part (b) is just the range of the ball, for the cart the catch it, it needs to travel the same distance as the ball has

    hope this helps
     
  4. Oct 1, 2011 #3
    Can't believe I couldn't do it before, I think I was just over thinking it.
    Thank you!!! :D
     
  5. Oct 1, 2011 #4
    no worries at all :)
     
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