A 14.0 g bulllet is fired at 396.1 m/s into a solid cylinder of mass 18.1 kg and a radius 0.45 m. The cylinder is initially at rest and is mounted on a fixed vertical axis that runs through it's center of mass. The line of motion of the bullet is perpendicular to the axle and at a distance 9.00 cm from the center. Find the angular velocity of the system after the bullet strikes and adheres to the surface of the cylinder.(adsbygoogle = window.adsbygoogle || []).push({});

First I converted the velocity to angular velocity by dividing by the radius.

I used conservation of angular momentum

[tex] (MR^2) \omega = (MR^2 + (1/2)MR^2) \omega [/tex]

(.14)(.09)(880.2) =((.14)(.09^2) + (1/2)(18.1)(.45^2)) \omega [/tex]

Solving for omega gave me .545 which wasn't right.. can someone tell me what I'm doing wrong? Thanks

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# Homework Help: Ballistic cylinder

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