A 13.0 g bullet is fired at 578.1 m/s into a solid cylinder of mass 24.1 kg and a radius 0.11 m. The cylinder is initially at rest and is mounted on fixed vertical axis that runs through it's center of mass.
The line of motion of the bullet is perpendicular to the axle and at a distance 2.20 cm from the center. Find the angular velocity of the system after the bullet strikes and adheres to the surface of the cylinder.
conservation of angular momentum
The Attempt at a Solution
.013 x (.022^2) (578.1/.11) = ((.013)(.022^2) + (.5)(24.1)(.11^2)) x W
I got .227rad/s as an answer but that was incorrect. Any ideas?