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Ballistic Pedulum - Finding Kinetic Energy Lost

  1. Nov 6, 2003 #1
    Here's a problem that I've been having trouble on for awhile and seem to be stuck. I was just wondering if someone could guide me or show me how to do this problem.

    The Ballistic pendulum is a device usd to measure the speed of a fast-moving projectile such as a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet is stopped by the block, and the entire system swings through the vertical distance, h. The mass of the bullet (m1=0.068kg), the mass of the pendulum (m2=0.256kg), h=6.2cm.

    Vo=(.324kg/.068kg) x (2 x 9.8 m/s^2 x .062m)^1/2 = 5.25m/s

    KEinitial= 1/2(.068kg x 5.25m/s)^2 = 0.937J

    KEfinal= 1/2(.324kg) x (2 x 9.8 m/s^2 x .062m) = .197J

    I got that far. I was wondering how do I find the kinetic energy lost from the info?
     
  2. jcsd
  3. Nov 6, 2003 #2

    jamesrc

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    Gold Member

    If I'm understanding your problem correctly, you're trying to solve for vo, the initial velocity of the bullet and the bullet/pendulum comes to a rest when it swings up to a height h.

    Let's call the mass of the bullet m and the mass of the block M and let's set our datum for potential energy at the initial height of the bullet/pendulum.

    First we need to consider the collision of the block and bullet using the conservation of momentum. This will give us the initial velocity of the ballistic pendulum:

    m*vo = (m+M)v

    Since we're neglecting things like air resistance and friction at the pendulum pivot, we know that all of this kinetic energy will be converted into potential energy:

    .5*(M+m)v^2 = (M+m)*g*h

    So find the expression for v in terms of vo, then plug into the 2nd equation to solve for vo.

    If you need the kinetic energy lost in the collision, you can calculate the kinetic energy before and after:

    KEb = .5*m*vo^2

    KEa = .5*(M+m)*v^2

    and find the difference.
     
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